7 cards, each one idea: what it is, a worked example, and the trap to dodge.
Work with sums
The only safe move: turn every average into a total (sum = avg x n), do the arithmetic on totals, then divide back.
Avg of 8 numbers is 20 (sum 160); two numbers averaging 26 leave: new sum 160 - 52 = 108, new avg 108/6 = 18.
Trap: Averages of averages cannot be averaged unless group sizes are equal.
Replacement shift
When one member is replaced and the average of n people moves by d, the newcomer differs from the leaver by n x d.
Avg weight of 10 rises by 2 kg when X replaces Y (60 kg): X = 60 + 10 x 2 = 80 kg.
Consecutive numbers
Evenly spaced numbers average to their middle value. For 1 to n the average is (n+1)/2.
Average of 21, 23, 25, 27, 29 = 25 (the middle).
Weighted average
Different group sizes need weights: avg = (n1 x a1 + n2 x a2)/(n1 + n2). The combined average always sits between the two, closer to the bigger group.
30 students avg 40, 20 students avg 60: (1200 + 1200)/50 = 48.
Trap: If your combined average is outside the two group averages, you made an arithmetic slip.
Average speed
Equal distances at x and y: average speed = 2xy/(x+y), the harmonic mean. Equal TIMES average to (x+y)/2.
60 km/h out, 40 km/h back: 2 x 60 x 40 / 100 = 48 km/h.
Trap: (60+40)/2 = 50 is the bait answer on almost every paper.
Correcting a misread value
One entry was wrong: correct average = wrong average + (correct value - wrong value)/n.
Avg of 20 numbers read as 50 with 83 typed as 38: 50 + 45/20 = 52.25.
New member joins
When someone joins and the average changes by d, the newcomer's value = old average + (n+1) x d, where n is the old count.
10 people avg 25; a joiner lifts it to 26: joiner = 25 + 11 x 1 = 36.