7 cards, each one idea: what it is, a worked example, and the trap to dodge.
The alligation cross
To hit mean m by mixing values c (cheap) and d (dear): ratio cheap:dear = (d - m):(m - c).
Rice at 30 and 40 mixed to cost 34: ratio = (40-34):(34-30) = 6:4 = 3:2.
Trap: Read the ratio toward the OPPOSITE value: the (d - m) part belongs to the cheaper ingredient.
Sanity check the mean
The target value must sit between the two ingredient values; if not, the mixture is impossible and you misread the question.
You cannot mix 20% and 30% solutions to get 35%.
Percent solutions
Treat concentrations as the values in the cross. Pure water is 0%, pure milk or acid is 100%.
20% and 50% solutions to make 30%: ratio = (50-30):(30-20) = 2:1.
Repeated replacement
Remove k liters from V liters and replace with water, n times: remaining original = V x (1 - k/V)^n.
40 L milk, replace 4 L with water twice: 40 x (0.9)^2 = 32.4 L milk.
Trap: The formula gives the ORIGINAL liquid left, not the water added.
Diluting to a target
Adding pure water only changes the denominator. Milk stays fixed: new concentration = milk / new total.
10 L of 90% milk diluted to 60%: milk 9 L fixed, total must be 15 L, add 5 L water.
Profit from watering
Selling a milk-water mix at the cost price of milk: gain% = (water / milk) x 100.
1 part water added to 4 parts milk, sold at cost: gain = 1/4 x 100 = 25%.
Trap: Gain is water over MILK, not water over total mixture.
Mixing two mixtures
When both inputs are already mixtures, track ONE component's amount through the blend, then recompute its share.
Equal volumes of 40% and 60% syrup: component = 0.4 + 0.6 = 1 per 2 L, so 50%.