Rapid Revision · Quantitative Aptitude

Time, Speed & Distance

Trains, boats and races are one identity, distance = speed x time, plus relative speed. Get the unit conversion reflex right and the rest is bookkeeping.

The 3-minute recap

If you read nothing else tonight, read these 6 lines.

  • km/h to m/s: multiply by 5/18. m/s to km/h: multiply by 18/5.
  • Same distance at x then y: average speed = 2xy/(x+y).
  • Opposite directions: speeds ADD. Same direction: speeds SUBTRACT.
  • Train crossing a pole: time = train length / speed. Platform: (train + platform)/speed.
  • Boats: downstream = b + s, upstream = b - s; b = (d+u)/2, s = (d-u)/2.
  • Same distance, speed ratio a:b means time ratio b:a.

Formula sheet

Every formula for time, speed & distance in one place, each labelled so you know exactly when to reach for it. Screenshot it the night before.

Core relation

speed = distance / time

Keep units consistent before you plug in.

Unit switch

km/h -> m/s : x 5/18 m/s -> km/h : x 18/5

Relative speed

same direction: |a - b| opposite: a + b

Train past a pole / platform

pole: t = L / speed platform: t = (L + P) / speed

Two trains crossing

t = (L1 + L2) / relative speed

Boats & streams

downstream = b + s upstream = b - s

b = boat speed in still water, s = stream speed.

Average speed

round trip = 2xy / (x + y)

Work through the cards

8 cards, each one idea: what it is, a worked example, and the trap to dodge.

Unit conversion reflex

Speeds in km/h, lengths in meters: convert first. km/h x 5/18 = m/s.

72 km/h = 72 x 5/18 = 20 m/s.

Trap: Answering in the wrong unit is the most common lost mark in train questions.

Train past a pole vs a platform

A pole (or a man) has no length: time = L_train / speed. A platform or bridge adds its length: time = (L_train + L_platform) / speed.

200 m train at 20 m/s crosses a 300 m platform in (200+300)/20 = 25 s.

Trap: Forgetting to add the train's OWN length to the platform length.

Relative speed

Two movers: opposite directions add speeds, same direction subtract. Two trains crossing each other cover the SUM of their lengths at relative speed.

150 m and 100 m trains at 30 and 20 m/s head-on: 250 / 50 = 5 s.

Boats and streams

Downstream speed d = boat + stream, upstream u = boat - stream. Recover boat = (d+u)/2 and stream = (d-u)/2.

d = 12, u = 8: boat 10 km/h, stream 2 km/h.

Speed ratio, time ratio

Over the same distance, time is inversely proportional to speed: speed ratio a:b means time ratio b:a.

Speeds 3:4 over one route: times 4:3.

Trap: Inverting the wrong ratio; slower speed always means larger time.

Late-early problems

Same start, same distance, two speeds, one late by t1 and one early by t2: distance = (s1 x s2 / (s2 - s1)) x (t1 + t2), with times in hours.

4 km/h is 10 min late, 5 km/h is 5 min early: d = (20/1) x (15/60) = 5 km.

Average speed is not the midpoint

Average speed = total distance / total time. Only equal TIMES let you average the speeds directly.

Half distance at 30, half at 60: 2 x 30 x 60 / 90 = 40 km/h.

Trap: 45 is the bait; harmonic mean 40 is the answer.

Races

'A beats B by 20 m in 100 m' means when A runs 100, B runs 80: speeds are 100:80 = 5:4. Convert beats-by statements into distance ratios.

A beats B by 10 m and B beats C by 10 m in 100 m: A beats C by 19 m (0.9 x 0.9 = 0.81).

Go deeper

A recap is not practice. These are the creators we rate for real depth on time, speed & distance; full credit to each.

One topic down. Keep the streak going.

Each recap takes 3 minutes; the full set covers everything the first round tests. And when the test is cleared, your resume takes the next screen.

Original content by OptiResume; facts and formulas are common knowledge, the wording is ours. Go-deeper links go to creators we rate; we are not affiliated with them.